Optimal. Leaf size=239 \[ \frac{5 \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}+1\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2} \]
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Rubi [A] time = 0.164189, antiderivative size = 239, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.533, Rules used = {290, 329, 297, 1162, 617, 204, 1165, 628} \[ \frac{5 \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}+1\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 290
Rule 329
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{\sqrt{x}}{\left (a+b x^2\right )^3} \, dx &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 \int \frac{\sqrt{x}}{\left (a+b x^2\right )^2} \, dx}{8 a}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{5 \int \frac{\sqrt{x}}{a+b x^2} \, dx}{32 a^2}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{5 \operatorname{Subst}\left (\int \frac{x^2}{a+b x^4} \, dx,x,\sqrt{x}\right )}{16 a^2}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}-\frac{5 \operatorname{Subst}\left (\int \frac{\sqrt{a}-\sqrt{b} x^2}{a+b x^4} \, dx,x,\sqrt{x}\right )}{32 a^2 \sqrt{b}}+\frac{5 \operatorname{Subst}\left (\int \frac{\sqrt{a}+\sqrt{b} x^2}{a+b x^4} \, dx,x,\sqrt{x}\right )}{32 a^2 \sqrt{b}}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{5 \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a}}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{x}\right )}{64 a^2 b}+\frac{5 \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a}}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{x}\right )}{64 a^2 b}+\frac{5 \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac{\sqrt{a}}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac{\sqrt{a}}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}+\frac{5 \log \left (\sqrt{a}-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \log \left (\sqrt{a}+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}\\ &=\frac{x^{3/2}}{4 a \left (a+b x^2\right )^2}+\frac{5 x^{3/2}}{16 a^2 \left (a+b x^2\right )}-\frac{5 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{32 \sqrt{2} a^{9/4} b^{3/4}}+\frac{5 \log \left (\sqrt{a}-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}-\frac{5 \log \left (\sqrt{a}+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{b} x\right )}{64 \sqrt{2} a^{9/4} b^{3/4}}\\ \end{align*}
Mathematica [C] time = 0.0048228, size = 29, normalized size = 0.12 \[ \frac{2 x^{3/2} \, _2F_1\left (\frac{3}{4},3;\frac{7}{4};-\frac{b x^2}{a}\right )}{3 a^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 175, normalized size = 0.7 \begin{align*}{\frac{1}{4\,a \left ( b{x}^{2}+a \right ) ^{2}}{x}^{{\frac{3}{2}}}}+{\frac{5}{16\,{a}^{2} \left ( b{x}^{2}+a \right ) }{x}^{{\frac{3}{2}}}}+{\frac{5\,\sqrt{2}}{128\,{a}^{2}b}\ln \left ({ \left ( x-\sqrt [4]{{\frac{a}{b}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{a}{b}}} \right ) \left ( x+\sqrt [4]{{\frac{a}{b}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{a}{b}}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{\frac{a}{b}}}}}}+{\frac{5\,\sqrt{2}}{64\,{a}^{2}b}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{a}{b}}}}}}+1 \right ){\frac{1}{\sqrt [4]{{\frac{a}{b}}}}}}+{\frac{5\,\sqrt{2}}{64\,{a}^{2}b}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{a}{b}}}}}}-1 \right ){\frac{1}{\sqrt [4]{{\frac{a}{b}}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.45506, size = 602, normalized size = 2.52 \begin{align*} -\frac{20 \,{\left (a^{2} b^{2} x^{4} + 2 \, a^{3} b x^{2} + a^{4}\right )} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{1}{4}} \arctan \left (\sqrt{-a^{5} b \sqrt{-\frac{1}{a^{9} b^{3}}} + x} a^{2} b \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{1}{4}} - a^{2} b \sqrt{x} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{1}{4}}\right ) - 5 \,{\left (a^{2} b^{2} x^{4} + 2 \, a^{3} b x^{2} + a^{4}\right )} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{1}{4}} \log \left (a^{7} b^{2} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{3}{4}} + \sqrt{x}\right ) + 5 \,{\left (a^{2} b^{2} x^{4} + 2 \, a^{3} b x^{2} + a^{4}\right )} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{1}{4}} \log \left (-a^{7} b^{2} \left (-\frac{1}{a^{9} b^{3}}\right )^{\frac{3}{4}} + \sqrt{x}\right ) - 4 \,{\left (5 \, b x^{3} + 9 \, a x\right )} \sqrt{x}}{64 \,{\left (a^{2} b^{2} x^{4} + 2 \, a^{3} b x^{2} + a^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.49284, size = 282, normalized size = 1.18 \begin{align*} \frac{5 \, b x^{\frac{7}{2}} + 9 \, a x^{\frac{3}{2}}}{16 \,{\left (b x^{2} + a\right )}^{2} a^{2}} + \frac{5 \, \sqrt{2} \left (a b^{3}\right )^{\frac{3}{4}} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a}{b}\right )^{\frac{1}{4}} + 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{a}{b}\right )^{\frac{1}{4}}}\right )}{64 \, a^{3} b^{3}} + \frac{5 \, \sqrt{2} \left (a b^{3}\right )^{\frac{3}{4}} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a}{b}\right )^{\frac{1}{4}} - 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{a}{b}\right )^{\frac{1}{4}}}\right )}{64 \, a^{3} b^{3}} - \frac{5 \, \sqrt{2} \left (a b^{3}\right )^{\frac{3}{4}} \log \left (\sqrt{2} \sqrt{x} \left (\frac{a}{b}\right )^{\frac{1}{4}} + x + \sqrt{\frac{a}{b}}\right )}{128 \, a^{3} b^{3}} + \frac{5 \, \sqrt{2} \left (a b^{3}\right )^{\frac{3}{4}} \log \left (-\sqrt{2} \sqrt{x} \left (\frac{a}{b}\right )^{\frac{1}{4}} + x + \sqrt{\frac{a}{b}}\right )}{128 \, a^{3} b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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